[STEP][剑桥数学入学考试][04-S2-Q3][Curve sketching][FP1] STEP

casperyc的马甲 4月前 5130

The curve CC has equation y=x(x+1)(x2)4. y = x(x+1)(x-2)^4. Determine the coordinates of all the stationary points of CC and the nature of each.

Sketch CC.

In separate diagrams draw sketches of the curves whose equations are:

  1. y2=x(x+1)(x2)4 y^2 = x(x+1)(x-2)^4
  2. y=x2(x2+1)(x22)4 y = x^2(x^2+1)(x^2-2)^4
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